What is inverse oflaplace arctan(s) ?

The answer to inverse oflaplace arctan(s) is -(sin(t))/t

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse oflaplace arctan(s)

inverse laplace

arctan (s)

- \frac{sin ( t )}{t}

Solution steps

L^{- 1} {arctan (s)}

Use Inverse Laplace Transform table:

L^{- 1} {F (s)} = - \frac{1}{t} L^{- 1} {F^{'} (s)}

L^{- 1} {arctan (s)} = - \frac{1}{t} L^{- 1} {(arctan (s))^{'}}

= - \frac{1}{t} L^{- 1} {(arctan (s))^{^{'}}}

(arctan (s))^{'} = \frac{1}{s ^{2} + 1}

= - \frac{1}{t} L^{- 1} {\frac{1}{s ^{2} + 1}}

L^{- 1} {\frac{1}{s ^{2} + 1}} : sin (t)

= - \frac{1}{t} sin (t)

= - \frac{sin ( t )}{t}

\int e^{- x} x^{2} d x

\frac{d}{d x} (3 a b^{2} x^{4})

\int 6 \cdot sin (2 x) - 3 \cdot cos (3 x) d x

x \frac{d y}{d x} = y

x d y = y + x (cos (\frac{y}{x}))^{2} d x

What is inverse oflaplace arctan(s) ?
The answer to inverse oflaplace arctan(s) is -(sin(t))/t