What is (\partial}{\partial x}(\frac{(x+y))/2) ?

The answer to (\partial}{\partial x}(\frac{(x+y))/2) is 1/2

(\partial}{\partial x}(\frac{(x+y))/2)

\frac{\partial}{\partial x} (\frac{( x + y )}{2})

\frac{1}{2}

Decimal

0.5

Solution steps

\frac{\partial}{\partial x} (\frac{( x + y )}{2})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{\partial}{\partial x} (x + y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{2} (\frac{\partial}{\partial x} (x) + \frac{\partial}{\partial x} (y))

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y) = 0

= \frac{1}{2} (1 + 0)

Simplify

= \frac{1}{2}

\int \frac{1}{x ( x ^{2} - 1 ) ^{\frac{3}{2}}} d x

\int_{7}^{14} 196 - x^{2} d x

s im pl i f y \frac{2 t}{2 + t}

\int \frac{x ^{3}}{x ^{4} + 9} d x

d er i v a t i v e f (x) = 9^{x} + e^{x}

What is (\partial}{\partial x}(\frac{(x+y))/2) ?
The answer to (\partial}{\partial x}(\frac{(x+y))/2) is 1/2