What is the tangent of y=-2x^3,(1,-2) ?

The tangent of y=-2x^3,(1,-2) is y=-6x+4

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tangent of y=-2x^3,(1,-2)

tangent

y = - 6 x + 4

Solution steps

Find the slope of

y = - 2 x^{3} : \frac{d y}{d x} = - 6 x^{2}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 6

Find the line with slope m=

- 6

and passing through

(1, - 2) : y = - 6 x + 4

y = - 6 x + 4

What is the tangent of y=-2x^3,(1,-2) ?
The tangent of y=-2x^3,(1,-2) is y=-6x+4