What is the derivative of (4x^3/3) ?

The derivative of (4x^3/3) is 4x^2

What is the first derivative of (4x^3/3) ?

The first derivative of (4x^3/3) is 4x^2

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\frac{d}{d x} (\frac{4 x ^{3}}{3})

4 x^{2}

Solution steps

\frac{d}{d x} (\frac{4 x ^{3}}{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{4}{3} \frac{d}{d x} (x^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{4}{3} \cdot 3 x^{3 - 1}

Simplify

\frac{4}{3} \cdot 3 x^{3 - 1} : 4 x^{2}

= 4 x^{2}

\frac{\partial}{\partial y} (z cos (x z))

\frac{d}{d x} ((x - 2)^{4} - 1)

\int x I n (1 + x)

(- 6, 7), (1, - 12)

\int_{0}^{4} \frac{8 t}{( t - 5 ) ^{2}} d t

What is the derivative of (4x^3/3) ?
The derivative of (4x^3/3) is 4x^2
What is the first derivative of (4x^3/3) ?
The first derivative of (4x^3/3) is 4x^2