What is the derivative of xln(x-x+1) ?

The derivative of xln(x-x+1) is ln(x)

What is the first derivative of xln(x-x+1) ?

The first derivative of xln(x-x+1) is ln(x)

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\frac{d}{d x} (x ln (x) - x + 1)

ln (x)

Solution steps

\frac{d}{d x} (x ln (x) - x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x ln (x)) - \frac{d x}{d x} + \frac{d}{d x} (1)

\frac{d}{d x} (x ln (x)) = ln (x) + 1

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= ln (x) + 1 - 1 + 0

Simplify

= ln (x)

\int \frac{( 1 + 15 x )}{x} d x

\int \frac{x + 5}{x + 1} d x

in v erse l a pl a ce - \frac{1}{s ( s ^{2} + 1 )}

y^{^{''}} + 4 y = 8 sin (2 x)

x \to 0.5 lim (\frac{sin ( x )}{x})

What is the derivative of xln(x-x+1) ?
The derivative of xln(x-x+1) is ln(x)
What is the first derivative of xln(x-x+1) ?
The first derivative of xln(x-x+1) is ln(x)