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Popular >

sum from n=1 to infinity of 1/(n^2+n)

Solution

n = 1 \sum \infty \frac{1}{n ^{2} + n}

Solution

1

Solution steps

n = 1 \sum \infty \frac{1}{n ^{2} + n}

Apply Telescoping Series Test:

1

= 1

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Frequently Asked Questions (FAQ)

What is the sum from n=1 to infinity of 1/(n^2+n) ?
The sum from n=1 to infinity of 1/(n^2+n) is 1