What is the limit as x approaches 0 of 9/x ?

The limit as x approaches 0 of 9/x is diverges

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limit as x approaches 0 of 9/x

x \to 0 lim (\frac{9}{x})

diverges

Solution steps

x \to 0 lim (\frac{9}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{9}{x}) = \infty

x \to 0 - lim (\frac{9}{x}) = - \infty

= diverges

\frac{d y}{d x} = - \frac{1 + x + y}{1 + x}

y^{^{''}} - 2 y^{^{'}} + 5 y = 0, y (\frac{π}{2}) = 0

\int 4 + x d x

\frac{d}{d x} (x^{2} + 2 x)

(y - x y^{2}) d x + x d y = 0

What is the limit as x approaches 0 of 9/x ?
The limit as x approaches 0 of 9/x is diverges