What is the integral of-(1/x) ?

The integral of-(1/x) is -ln|x|+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of-(1/x)

\int - (\frac{1}{x}) d x

- ln ∣ x ∣ + C

Solution steps

\int - \frac{1}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= - ln ∣ x ∣

Add a constant to the solution

= - ln ∣ x ∣ + C

\int - \frac{1}{t} d t

\frac{d}{d x} ((sin (3 x))^{2})

f (x) = x x - x^{2}

e^{x}, ln (12)

\frac{d}{d x} (x^{2} sin (\frac{1}{x ^{2}}))