What is the derivative of 8x^3+4x^2-5x+4 ?

The derivative of 8x^3+4x^2-5x+4 is 24x^2+8x-5

What is the first derivative of 8x^3+4x^2-5x+4 ?

The first derivative of 8x^3+4x^2-5x+4 is 24x^2+8x-5

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\frac{d}{d x} (8 x^{3} + 4 x^{2} - 5 x + 4)

24 x^{2} + 8 x - 5

Solution steps

\frac{d}{d x} (8 x^{3} + 4 x^{2} - 5 x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 x^{3}) + \frac{d}{d x} (4 x^{2}) - \frac{d}{d x} (5 x) + \frac{d}{d x} (4)

\frac{d}{d x} (8 x^{3}) = 24 x^{2}

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (5 x) = 5

\frac{d}{d x} (4) = 0

= 24 x^{2} + 8 x - 5 + 0

Simplify

= 24 x^{2} + 8 x - 5

arcsin (5 x)

\frac{( 8 x ) ^{9}}{9}

\int - 3 y d y

(- 3)^{^{'}}

\frac{d}{d x} ((4 - 2 x) (- x^{3} - 2 x^{2} + 1))

What is the derivative of 8x^3+4x^2-5x+4 ?
The derivative of 8x^3+4x^2-5x+4 is 24x^2+8x-5
What is the first derivative of 8x^3+4x^2-5x+4 ?
The first derivative of 8x^3+4x^2-5x+4 is 24x^2+8x-5