What is the tangent of f(x)=(3x^3-4x^2+5x-9)^2,\at x=2 ?

The tangent of f(x)=(3x^3-4x^2+5x-9)^2,\at x=2 is y=450x-819

Popular >

tangent of f(x)=(3x^3-4x^2+5x-9)^2,\at x=2

tangent of

f (x) = (3 x^{3} - 4 x^{2} + 5 x - 9)^{2}, at x = 2

y = 450 x - 819

Solution steps

Find the tangent point:

(2, 81)

Find the slope of

f (x) = (3 x^{3} - 4 x^{2} + 5 x - 9)^{2} : \frac{df ( x )}{d x} = 2 (3 x^{3} - 4 x^{2} + 5 x - 9) (9 x^{2} - 8 x + 5)

Compute the slope of

f (x) = (3 x^{3} - 4 x^{2} + 5 x - 9)^{2}

x = 2 : m = 450

Find the line with slope m=

450

and passing through

(2, 81) : y = 450 x - 819

y = 450 x - 819

x \to 2 lim (x^{2} + 6 x + 5)

x \to 0 + lim (x^{13 x})

x \to 4 lim (6)

\frac{\partial}{\partial y} (2 y - \frac{3}{y ^{2}} + x)

\int \frac{x ^{4} + 3 x}{x ^{2}} d x

What is the tangent of f(x)=(3x^3-4x^2+5x-9)^2,\at x=2 ?
The tangent of f(x)=(3x^3-4x^2+5x-9)^2,\at x=2 is y=450x-819