What is inverse oflaplace 3*e^{-s} ?

The answer to inverse oflaplace 3*e^{-s} is 3\delta(t-1)

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inverse oflaplace 3*e^{-s}

inverse laplace

3 \cdot e^{- s}

3 δ (t - 1)

Solution steps

L^{- 1} {3 e^{- s}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 3 L^{- 1} {e^{- s}}

L^{- 1} {e^{- s}} : δ (t - 1)

= 3 δ (t - 1)

x (x^{2} - 4 x + 5)^{4}, at x = 2

x \to 4 + lim (\frac{x + 2}{x - 4})

\int_{3}^{5} x \cdot \frac{x}{8} d x

\frac{8}{sin ( x ) + cos ( x )}

f (x) = 4 x^{2} - 5 x (- 1.9)

What is inverse oflaplace 3*e^{-s} ?
The answer to inverse oflaplace 3*e^{-s} is 3\delta(t-1)