What is laplacetransform-3sin(3t) ?

The answer to laplacetransform-3sin(3t) is -9/(s^2+9)

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laplacetransform-3sin(3t)

laplace transform

- 3 sin (3 t)

- \frac{9}{s ^{2} + 9}

Solution steps

L {- 3 sin (3 t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= - 3 L {sin (3 t)}

L {sin (3 t)} : \frac{3}{s ^{2} + 9}

= - 3 \cdot \frac{3}{s ^{2} + 9}

Refine

- 3 \frac{3}{s ^{2} + 9} : - \frac{9}{s ^{2} + 9}

= - \frac{9}{s ^{2} + 9}

\frac{d}{d x} (sin^{- 2} (x))

x \to 6 + lim (\frac{1}{x - 6})

\int \frac{1}{( x + 4 ) ^{2} ( x - 2 )} d x

ma c l a u r in tan (x)

\int (e^{2 x} cos (e^{x})) d x

What is laplacetransform-3sin(3t) ?
The answer to laplacetransform-3sin(3t) is -9/(s^2+9)