What is the solution for y^{''}+6/x y^'+4/(x^2)y=0 ?

The solution for y^{''}+6/x y^'+4/(x^2)y=0 is y=(c_{1})/x+(c_{2})/(x^4)

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y^{''}+6/x y^'+4/(x^2)y=0

y^{^{''}} + \frac{6}{x} y^{^{'}} + \frac{4}{x ^{2}} y = 0

y = \frac{c _{1}}{x} + \frac{c _{2}}{x ^{4}}

Solution steps

y^{''} (x) + \frac{6}{x} y^{'} (x) + \frac{4}{x ^{2}} y = 0

Solve linear ODE:

y = \frac{c _{1}}{x} + \frac{c _{2}}{x ^{4}}

y = \frac{c _{1}}{x} + \frac{c _{2}}{x ^{4}}

f (x) = x^{2} - 4 x + 2

x \to 1 lim (e^{(x^{3} - x)})

\frac{d}{d x} (e^{π x})

\frac{d}{d x} (\frac{1 + 2 y ^{2}}{y sin ( x )})

\frac{d}{d x} (\frac{- \frac{5}{2}}{x ^{2}} + 5^{x})

What is the solution for y^{''}+6/x y^'+4/(x^2)y=0 ?
The solution for y^{''}+6/x y^'+4/(x^2)y=0 is y=(c_{1})/x+(c_{2})/(x^4)