What is the limit as h approaches 0 of 1/(h+1) ?

The limit as h approaches 0 of 1/(h+1) is 1

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limit as h approaches 0 of 1/(h+1)

h \to 0 lim (\frac{1}{h + 1})

1

Solution steps

h \to 0 lim (\frac{1}{h + 1})

Plug in the value

h = 0

= \frac{1}{0 + 1}

Simplify

= 1

\int x^{- 3} (x + 1) d x

\int_{0}^{1} 8^{2 x} d x

d er i v a t i v e 5 x sin (x^{2})

\int \frac{e ^{x}}{x} d x

d er i v a t i v e f (x) = 8 x e^{x} - 8 e^{x}

What is the limit as h approaches 0 of 1/(h+1) ?
The limit as h approaches 0 of 1/(h+1) is 1