What is the solution for y^'+xy=xy^3 ?

The solution for y^'+xy=xy^3 is y=sqrt(1/(e^{x^2-c_{1))+1}},y=-sqrt(1/(e^{x^2-c_{1))+1}}

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y^'+xy=xy^3

y^{^{'}} + x y = x y^{3}

y = \frac{1}{e ^{x^{2} - c_{1}} + 1}, y = - \frac{1}{e ^{x^{2} - c_{1}} + 1}

Solution steps

y^{'} (x) + x y = x y^{3}

Solve Bernoulli ODE:

y = \frac{1}{e ^{x^{2} - c_{1}} + 1}, y = - \frac{1}{e ^{x^{2} - c_{1}} + 1}

y = \frac{1}{e ^{x^{2} - c_{1}} + 1}, y = - \frac{1}{e ^{x^{2} - c_{1}} + 1}

x \to 0 lim (\frac{x}{x + 7})

y^{^{'}} = 1 + y - 2 x + 3

\frac{d}{d x} (- 3 cot (2 x) sec (2 x))

\int \frac{1}{3 x + 2} d x

\int_{0}^{2} (x - 3)^{2} - (x - 1)^{2} d x

What is the solution for y^'+xy=xy^3 ?
The solution for y^'+xy=xy^3 is y=sqrt(1/(e^{x^2-c_{1))+1}},y=-sqrt(1/(e^{x^2-c_{1))+1}}