What is the integral from-infinity to 0 of 1/(7-9x) ?

The integral from-infinity to 0 of 1/(7-9x) is diverges

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integral from-infinity to 0 of 1/(7-9x)

\int_{- \infty}^{0} \frac{1}{7 - 9 x} d x

diverges

Solution steps

\int_{- \infty}^{0} \frac{1}{7 - 9 x} d x

Compute the indefinite integral:

\int \frac{1}{7 - 9 x} d x = - \frac{1}{9} ln ∣ 7 - 9 x ∣ + C

Compute the boundaries:

\int_{- \infty}^{0} \frac{1}{7 - 9 x} d x =

diverges

= diverges

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\frac{d}{d x} (8^{4 - x^{2}})

(x^{2} - 35)^{6}

\frac{d}{d x} (\frac{1}{sin ( x ) + cos ( x )})

y = x^{2} + 2, y = - x, x = 0, x = 1

What is the integral from-infinity to 0 of 1/(7-9x) ?
The integral from-infinity to 0 of 1/(7-9x) is diverges