What is the integral from 1 to 11 of 1/(x-8) ?

The integral from 1 to 11 of 1/(x-8) is diverges

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integral from 1 to 11 of 1/(x-8)

\int_{1}^{11} \frac{1}{x - 8} d x

diverges

Solution steps

\int_{1}^{11} \frac{1}{x - 8} d x

Find undefined (singularity) points:

x = 8

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{1}^{8} \frac{1}{x - 8} d x + \int_{8}^{11} \frac{1}{x - 8} d x

\int_{1}^{8} \frac{1}{x - 8} d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

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n = 1 \sum \infty \frac{2}{2 ^{n}}

What is the integral from 1 to 11 of 1/(x-8) ?
The integral from 1 to 11 of 1/(x-8) is diverges