What is area (x^2)/8 ,2x^2,y=2,y=0 ?

The answer to area (x^2)/8 ,2x^2,y=2,y=0 is No Solution

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area (x^2)/8 ,2x^2,y=2,y=0

area

\frac{x ^{2}}{8}, 2 x^{2}, y = 2, y = 0

No Solution

Solution steps

To find the intersection points solve

f_{i} (x) = f_{j} (x)

2 = 0 :

False

2 = \frac{x ^{2}}{8} : x = 4, x = - 4

2 = 2 x^{2} : x = 1, x = - 1

0 = \frac{x ^{2}}{8} : x = 0

0 = 2 x^{2} : x = 0

\frac{x ^{2}}{8} = 2 x^{2} : x = 0

Curves not bounded

= No Solution

(1 - x^{2})^{\frac{1}{2}}

2 x y \frac{d y}{d x} = 3

\int \frac{ln ( x ) - 1}{x} d x

x \to 1 lim (3 x - 6)

What is area (x^2)/8 ,2x^2,y=2,y=0 ?
The answer to area (x^2)/8 ,2x^2,y=2,y=0 is No Solution