What is the derivative of f(x)=sin(x^3) ?

The derivative of f(x)=sin(x^3) is cos(x^3)*3x^2

What is the first derivative of f(x)=sin(x^3) ?

The first derivative of f(x)=sin(x^3) is cos(x^3)*3x^2

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derivative of

f (x) = sin (x^{3})

cos (x^{3}) \cdot 3 x^{2}

Solution steps

\frac{d}{d x} (sin (x^{3}))

Apply the chain rule:

cos (x^{3}) \frac{d}{d x} (x^{3})

= cos (x^{3}) \frac{d}{d x} (x^{3})

\frac{d}{d x} (x^{3}) = 3 x^{2}

= cos (x^{3}) \cdot 3 x^{2}

\frac{\partial}{\partial x} (Q (x) 0. 5^{\frac{x}{35}})

n = 0 \sum \infty \frac{n}{n ^{2} + 1}

f (x) = (3 x^{2} + 4 x + 1)^{10}

f (x) = 6 x^{2} + 3 x - 4

\int x (sin (x^{2})) d x

What is the derivative of f(x)=sin(x^3) ?
The derivative of f(x)=sin(x^3) is cos(x^3)*3x^2
What is the first derivative of f(x)=sin(x^3) ?
The first derivative of f(x)=sin(x^3) is cos(x^3)*3x^2