What is the derivative of 2cos(-2x) ?

The derivative of 2cos(-2x) is -4sin(2x)

What is the first derivative of 2cos(-2x) ?

The first derivative of 2cos(-2x) is -4sin(2x)

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\frac{d}{d x} (2 cos (- 2 x))

- 4 sin (2 x)

Solution steps

\frac{d}{d x} (2 cos (- 2 x))

Simplify

2 cos (- 2 x) : 2 cos (2 x)

= \frac{d}{d x} (2 cos (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (cos (2 x))

Apply the chain rule:

- sin (2 x) \frac{d}{d x} (2 x)

= - sin (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= 2 (- sin (2 x) \cdot 2)

Simplify

= - 4 sin (2 x)

\int \frac{34 x ^{2}}{( 2 x + 1 ) ( x ^{2} + 4 )} d x

y^{^{'}} = - 3 x y^{3}

\int (6 x y) d x

e^{3 x}, 2

\frac{d}{d x} (x^{p (x)})

What is the derivative of 2cos(-2x) ?
The derivative of 2cos(-2x) is -4sin(2x)
What is the first derivative of 2cos(-2x) ?
The first derivative of 2cos(-2x) is -4sin(2x)