What is the tangent of y=2x^2-x+1,(1,2) ?

The tangent of y=2x^2-x+1,(1,2) is y=3x-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y=2x^2-x+1,(1,2)

tangent of

y = 2 x^{2} - x + 1, (1, 2)

y = 3 x - 1

Solution steps

Find the slope of

y = 2 x^{2} - x + 1 : \frac{d y}{d x} = 4 x - 1

Compute the slope of

y = 2 x^{2} - x + 1

(1, 2) : m = 3

Find the line with slope m=

3

and passing through

(1, 2) : y = 3 x - 1

y = 3 x - 1

x \to 1 lim ((x^{2} + x)^{2})

f (t) = t e^{5 - 2 t}

\frac{d}{d a} (sin (a) cos (a))

(x^{2} + 2 x y) d x + x d y = 0

\frac{\partial}{\partial x} (x^{4} + 2 x y^{9})

What is the tangent of y=2x^2-x+1,(1,2) ?
The tangent of y=2x^2-x+1,(1,2) is y=3x-1