What is the integral from 0 to 9 of piy^3 ?

The integral from 0 to 9 of piy^3 is (6561pi)/4

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integral from 0 to 9 of piy^3

\int_{0}^{9} π y^{3} d y

\frac{6561 π}{4}

Solution steps

\int_{0}^{9} π y^{3} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= π \cdot \int_{0}^{9} y^{3} d y

Apply the Power Rule

: [\frac{y ^{4}}{4}]_{0}^{9}

= π [\frac{y ^{4}}{4}]_{0}^{9}

Compute the boundaries:

\frac{6561}{4}

= π \frac{6561}{4}

Simplify

= \frac{6561 π}{4}

x^{3} - 10 x, 6 x, [- 4, 4]

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What is the integral from 0 to 9 of piy^3 ?
The integral from 0 to 9 of piy^3 is (6561pi)/4