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Popular >

derivative of Axcos(x+Bcos(x))

Solution

\frac{d}{d x} (A x cos (x) + B cos (x))

Solution

A (cos (x) - x sin (x)) - B sin (x)

Solution steps

\frac{d}{d x} (A x cos (x) + B cos (x))

Treat

A, B

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (A x cos (x)) + \frac{d}{d x} (B cos (x))

\frac{d}{d x} (A x cos (x)) = A (cos (x) - x sin (x))

\frac{d}{d x} (B cos (x)) = - B sin (x)

= A (cos (x) - x sin (x)) - B sin (x)

Popular Examples

limit as x approaches 1 of 1/(x-1)

x \to 1 lim (\frac{1}{x - 1})

inverse oflaplace 1/(2s+1)inverse laplace

\frac{1}{2 s + 1}

integral of (-x)/(sqrt(x+1))

\int \frac{- x}{x + 1} d x

integral of (sin(x)-2cos(x))

\int (sin (x) - 2 cos (x)) d x

inverse oflaplace (2s)/(s^2+4)inverse laplace

\frac{2 s}{s ^{2} + 4}

Frequently Asked Questions (FAQ)

What is the derivative of Axcos(x+Bcos(x)) ?
The derivative of Axcos(x+Bcos(x)) is A(cos(x)-xsin(x))-Bsin(x)
What is the first derivative of Axcos(x+Bcos(x)) ?
The first derivative of Axcos(x+Bcos(x)) is A(cos(x)-xsin(x))-Bsin(x)