What is the derivative of (3x+7^5) ?

The derivative of (3x+7^5) is 15(3x+7)^4

What is the first derivative of (3x+7^5) ?

The first derivative of (3x+7^5) is 15(3x+7)^4

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\frac{d}{d x} ((3 x + 7)^{5})

15 (3 x + 7)^{4}

Solution steps

\frac{d}{d x} ((3 x + 7)^{5})

Apply the chain rule:

5 (3 x + 7)^{4} \frac{d}{d x} (3 x + 7)

= 5 (3 x + 7)^{4} \frac{d}{d x} (3 x + 7)

\frac{d}{d x} (3 x + 7) = 3

= 5 (3 x + 7)^{4} \cdot 3

Simplify

= 15 (3 x + 7)^{4}

n = 1 \sum \infty \frac{1}{10}

\int \frac{x ^{5}}{2} d x

\int \frac{x \cdot e ^{x}}{( 1 + x ) ^{2}} d x

(8 x)^{4 x}

\frac{\partial}{\partial x} (2 x sin (2 y))

What is the derivative of (3x+7^5) ?
The derivative of (3x+7^5) is 15(3x+7)^4
What is the first derivative of (3x+7^5) ?
The first derivative of (3x+7^5) is 15(3x+7)^4