What is the derivative of f(x)=2x+4x^{-1} ?

The derivative of f(x)=2x+4x^{-1} is 2-4/(x^2)

What is the first derivative of f(x)=2x+4x^{-1} ?

The first derivative of f(x)=2x+4x^{-1} is 2-4/(x^2)

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derivative of

f (x) = 2 x + 4 x^{- 1}

2 - \frac{4}{x ^{2}}

Solution steps

\frac{d}{d x} (2 x + 4 x^{- 1})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) + \frac{d}{d x} (4 x^{- 1})

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (4 x^{- 1}) = - \frac{4}{x ^{2}}

= 2 - \frac{4}{x ^{2}}

f (x) = 4 x e^{x}

\frac{d}{d x} (x^{3} sin^{2} (5 x))

\int ln (5 x^{2}) d x

\int_{1}^{2} 3 4 x^{2} - 3 d x

f (x) = 2 x, 1, 3

What is the derivative of f(x)=2x+4x^{-1} ?
The derivative of f(x)=2x+4x^{-1} is 2-4/(x^2)
What is the first derivative of f(x)=2x+4x^{-1} ?
The first derivative of f(x)=2x+4x^{-1} is 2-4/(x^2)