What is the integral of-9/(x^{10)} ?

The integral of-9/(x^{10)} is 1/(x^9)+C

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integral of-9/(x^{10)}

\int - \frac{9}{x ^{10}} d x

\frac{1}{x ^{9}} + C

Solution steps

\int - \frac{9}{x ^{10}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 9 \cdot \int \frac{1}{x ^{10}} d x

Apply the Power Rule

: - \frac{1}{9 x ^{9}}

= - 9 (- \frac{1}{9 x ^{9}})

Simplify

- 9 (- \frac{1}{9 x ^{9}}) : \frac{1}{x ^{9}}

= \frac{1}{x ^{9}}

Add a constant to the solution

= \frac{1}{x ^{9}} + C

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