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Popular >

y^'=2x^2

Solution

y^{^{'}} = 2 x^{2}

Solution

y = \frac{2 x ^{3}}{3} + c_{1}

Solution steps

y^{'} (x) = 2 x^{2}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int 2 x^{2} d x

\int 2 x^{2} d x = \frac{2 x ^{3}}{3} + c_{1}

y = \frac{2 x ^{3}}{3} + c_{1}

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Frequently Asked Questions (FAQ)

What is the solution for y^'=2x^2 ?
The solution for y^'=2x^2 is y=(2x^3)/3+c_{1}