What is the derivative of 3/(2x) ?

The derivative of 3/(2x) is -3/(2x^2)

What is the first derivative of 3/(2x) ?

The first derivative of 3/(2x) is -3/(2x^2)

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\frac{d}{d x} (\frac{3}{2 x})

- \frac{3}{2 x ^{2}}

Solution steps

\frac{d}{d x} (\frac{3}{2 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{3}{2} \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{3}{2} \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{3}{2} (- 1 \cdot x^{- 1 - 1})

Simplify

\frac{3}{2} (- 1 \cdot x^{- 1 - 1}) : - \frac{3}{2 x ^{2}}

= - \frac{3}{2 x ^{2}}

x \to 1 lim (- 3 a x + b)

\frac{d}{d x} ((13 x^{2} - 26 x + 26) e^{x})

\frac{d}{d x} (e^{\frac{x}{2}} + 4 x)

\int_{0}^{4.5} 100 x d x

4 x^{2} - 2 x, at x = - 1

What is the derivative of 3/(2x) ?
The derivative of 3/(2x) is -3/(2x^2)
What is the first derivative of 3/(2x) ?
The first derivative of 3/(2x) is -3/(2x^2)