limit as x approaches 2+of (2x+1)/(x-2)

Lösung

x \to 2 + lim (\frac{2 x + 1}{x - 2})

\infty

Schritte zur Lösung

x \to 2 + lim (\frac{2 x + 1}{x - 2})

\frac{2 x + 1}{x - 2} = (2 x + 1) \frac{1}{x - 2}

= x \to 2 + lim ((2 x + 1) \frac{1}{x - 2})

x \to a lim [f (x) \cdot g (x)] = x \to a lim f (x) \cdot x \to a lim g (x)

mit Einschränkung des unbestimmten Ausdrucks

= x \to 2 + lim (2 x + 1) \cdot x \to 2 + lim (\frac{1}{x - 2})

x \to 2 + lim (2 x + 1) = 5

x \to 2 + lim (\frac{1}{x - 2}) = \infty

= 5 \cdot \infty

Wende die Unendlichkeitseigenschaft an:

c \cdot \infty = \infty

= \infty

in v erse l a pl a ce \frac{e ^{- 2 x}}{2 x ^{2} + 1}

y^{^{''}} - 3 y^{^{'}} - 10 y = 4 e^{4 t}, y (0) = 0, y^{^{'}} (0) = 0

n = 9 \sum \infty e^{5 - 6 n}

\int (\frac{1}{1 + 9 x ^{2}}) d x

\frac{d}{d x} (5 sin (- 4 x))