What is the tangent of f(x)=4+3x-2x^2,\at x=2 ?

The tangent of f(x)=4+3x-2x^2,\at x=2 is y=-5x+12

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tangent of f(x)=4+3x-2x^2,\at x=2

tangent

y = - 5 x + 12

Solution steps

Find the tangent point:

(2, 2)

Find the slope of

f (x) = 4 + 3 x - 2 x^{2} : \frac{df ( x )}{d x} = - 4 x + 3

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 5

Find the line with slope m=

- 5

and passing through

(2, 2) : y = - 5 x + 12

y = - 5 x + 12

What is the tangent of f(x)=4+3x-2x^2,\at x=2 ?
The tangent of f(x)=4+3x-2x^2,\at x=2 is y=-5x+12