What is the integral from 1 to infinity of 1/(x^9) ?

The integral from 1 to infinity of 1/(x^9) is 1/8

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integral from 1 to infinity of 1/(x^9)

\int_{1}^{\infty} \frac{1}{x ^{9}} d x

\frac{1}{8}

Solution steps

\int_{1}^{\infty} \frac{1}{x ^{9}} d x

Compute the indefinite integral:

\int \frac{1}{x ^{9}} d x = - \frac{1}{8 x ^{8}} + C

Compute the boundaries:

\int_{1}^{\infty} \frac{1}{x ^{9}} d x = 0 - (- \frac{1}{8})

= 0 - (- \frac{1}{8})

Simplify

= \frac{1}{8}

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\frac{d}{d x} (7 x (x^{3} - 3 x + 2))

\int x^{2} (x + 3)^{2} d x

y = e^{- x}, y = 0, x = 0, x = ln (5)

x \to 3 lim (a x + 3)

What is the integral from 1 to infinity of 1/(x^9) ?
The integral from 1 to infinity of 1/(x^9) is 1/8