integral of (11)/(x^3-27)

Lösung

\int \frac{11}{x ^{3} - 27} d x

11 (\frac{1}{27} ln ∣ x - 3 ∣ - \frac{1}{54} ln 4 x^{2} + 12 x + 36 - \frac{1}{9 3} arctan (\frac{2}{3 3} x + \frac{1}{3})) + C

Schritte zur Lösung

\int \frac{11}{x ^{3} - 27} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 11 \cdot \int \frac{1}{x ^{3} - 27} d x

Ermittle den Partialbruch von

\frac{1}{x ^{3} - 27} : \frac{1}{27 ( x - 3 )} + \frac{- x - 6}{27 ( x ^{2} + 3 x + 9 )}

= 11 \cdot \int \frac{1}{27 ( x - 3 )} + \frac{- x - 6}{27 ( x ^{2} + 3 x + 9 )} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 11 (\int \frac{1}{27 ( x - 3 )} d x + \int \frac{- x - 6}{27 ( x ^{2} + 3 x + 9 )} d x)

\int \frac{1}{27 ( x - 3 )} d x = \frac{1}{27} ln ∣ x - 3 ∣

\int \frac{- x - 6}{27 ( x ^{2} + 3 x + 9 )} d x = \frac{1}{54 3} (- 3 ln 4 x^{2} + 12 x + 36 - 6 arctan (\frac{2}{3 3} x + \frac{1}{3}))

= 11 (\frac{1}{27} ln ∣ x - 3 ∣ + \frac{1}{54 3} (- 3 ln 4 x^{2} + 12 x + 36 - 6 arctan (\frac{2}{3 3} x + \frac{1}{3})))

Multipliziere aus

\frac{1}{54 3} (- 3 ln 4 x^{2} + 12 x + 36 - 6 arctan (\frac{2}{3 3} x + \frac{1}{3})) : - \frac{1}{54} ln 4 x^{2} + 12 x + 36 - \frac{1}{9 3} arctan (\frac{2}{3 3} x + \frac{1}{3})

= 11 (\frac{1}{27} ln ∣ x - 3 ∣ - \frac{1}{54} ln 4 x^{2} + 12 x + 36 - \frac{1}{9 3} arctan (\frac{2}{3 3} x + \frac{1}{3}))

Füge eine Konstante zur Lösung hinzu

= 11 (\frac{1}{27} ln ∣ x - 3 ∣ - \frac{1}{54} ln 4 x^{2} + 12 x + 36 - \frac{1}{9 3} arctan (\frac{2}{3 3} x + \frac{1}{3})) + C

\frac{d}{d x} (\frac{- 3 x ^{5} - x ^{4} - x ^{3} + 4 x ^{2}}{x ^{2}})

y^{^{''}} + 4 y^{^{'}} + 4 y = 0, y (0) = - 1, y^{^{'}} (0) = 0

\frac{\partial}{\partial x} (\frac{4 x - 2 y}{2 x ^{2} + 3 y})

\int_{0}^{4} \frac{1}{x ^{2} + x - 6} d x

\int_{1}^{4} (4 x^{2} + x) d x