What is the limit as x approaches 3 of (6x)/(x^2-9) ?

The limit as x approaches 3 of (6x)/(x^2-9) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 3 of (6x)/(x^2-9)

x \to 3 lim (\frac{6 x}{x ^{2} - 9})

diverges

Solution steps

x \to 3 lim (\frac{6 x}{x ^{2} - 9})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 3 + lim (\frac{6 x}{x ^{2} - 9}) = \infty

x \to 3 - lim (\frac{6 x}{x ^{2} - 9}) = - \infty

= diverges

\int - t^{2} d t

\int_{1}^{5} \frac{1}{3 x + 1} d x

\frac{d}{d x} (\frac{4 x ^{2} + 2 x + 2}{x})

\int 1 + tan^{2} (x) d x

\int_{1}^{e} ln (2 x) d x

What is the limit as x approaches 3 of (6x)/(x^2-9) ?
The limit as x approaches 3 of (6x)/(x^2-9) is diverges