What is the d/(ds)(6/(s^2+36)) ?

The d/(ds)(6/(s^2+36)) is -(12s)/((s^2+36)^2)

What is the first d/(ds)(6/(s^2+36)) ?

The first d/(ds)(6/(s^2+36)) is -(12s)/((s^2+36)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d s} (\frac{6}{s ^{2} + 36})

- \frac{12 s}{( s ^{2} + 36 ) ^{2}}

Solution steps

\frac{d}{d s} (\frac{6}{s ^{2} + 36})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d s} (\frac{1}{s ^{2} + 36})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 6 \frac{d}{d s} ((s^{2} + 36)^{- 1})

Apply the chain rule:

- \frac{1}{( s ^{2} + 36 ) ^{2}} \frac{d}{d s} (s^{2} + 36)

= - \frac{1}{( s ^{2} + 36 ) ^{2}} \frac{d}{d s} (s^{2} + 36)

\frac{d}{d s} (s^{2} + 36) = 2 s

= 6 (- \frac{1}{( s ^{2} + 36 ) ^{2}} \cdot 2 s)

Simplify

6 (- \frac{1}{( s ^{2} + 36 ) ^{2}} \cdot 2 s) : - \frac{12 s}{( s ^{2} + 36 ) ^{2}}

= - \frac{12 s}{( s ^{2} + 36 ) ^{2}}

\frac{d ^{2}}{d x ^{2}} (x^{2} + 16)

\int \frac{3 x ^{2} + 1}{2 x} d x

\int \frac{5 x ^{3} + 7 x}{x - 1} d x

\int \frac{1}{( x + 4 ) ( x - 4 )} d x

y = 2 x arccos (x) - 2 1 - x^{2}

What is the d/(ds)(6/(s^2+36)) ?
The d/(ds)(6/(s^2+36)) is -(12s)/((s^2+36)^2)
What is the first d/(ds)(6/(s^2+36)) ?
The first d/(ds)(6/(s^2+36)) is -(12s)/((s^2+36)^2)