What is the tangent of 8/x+6 ?

The tangent of 8/x+6 is y=-8/(a_{0)^2}x+(16)/(a_{0)}+6

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tangent of 8/x+6

tangent of

\frac{8}{x} + 6

y = - \frac{8}{a _{0}^{2}} x + \frac{16}{a _{0}} + 6

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{8}{a _{0}} + 6)

Find the slope of

y = \frac{8}{x} + 6 : \frac{d y}{d x} = - \frac{8}{x ^{2}}

Compute the slope of

y = \frac{8}{x} + 6

x = a_{0} : m = - \frac{8}{a _{0}^{2}}

Find the line with slope m=

- \frac{8}{a _{0}^{2}}

and passing through

(a_{0}, \frac{8}{a _{0}} + 6) : y = - \frac{8}{a _{0}^{2}} x + \frac{16}{a _{0}} + 6

y = - \frac{8}{a _{0}^{2}} x + \frac{16}{a _{0}} + 6

f (x) = \frac{1}{x ^{2}}, (2, \frac{1}{4})

\frac{d}{d x} (x^{3} + x + 1)

n = 1 \sum \infty n^{2} \cdot e^{- n}

\int_{1}^{2} 7 4 x^{2} - 3 d x

What is the tangent of 8/x+6 ?
The tangent of 8/x+6 is y=-8/(a_{0)^2}x+(16)/(a_{0)}+6