What is area (sqrt(x))/2 ,3x^2-1,0,0.5 ?

The answer to area (sqrt(x))/2 ,3x^2-1,0,0.5 is 0.49285…

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area (sqrt(x))/2 ,3x^2-1,0,0.5

area

\frac{x}{2}, 3 x^{2} - 1, 0, 0.5

0.49285 \dots

Solution steps

Apply the area formula:

\int_{0}^{0.5} \frac{x}{2} - (3 x^{2} - 1) d x

Solve

\int_{0}^{0.5} \frac{x}{2} - (3 x^{2} - 1) d x : 0.49285 \dots

The area is:

= 0.49285 \dots

- 9 x + 5

\frac{s ^{2} - 4}{s + 1}

\int \frac{1}{cos ( θ )} d θ

\int 2 y - x^{2} d x

y = \frac{1}{( 1 + x ^{2} ) , at ( - 1 , \frac{1}{2} )}

What is area (sqrt(x))/2 ,3x^2-1,0,0.5 ?
The answer to area (sqrt(x))/2 ,3x^2-1,0,0.5 is 0.49285…