What is the tangent of f(x)=sqrt(7x+2),(2,4) ?

The tangent of f(x)=sqrt(7x+2),(2,4) is y= 7/8 x+9/4

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tangent of f(x)=sqrt(7x+2),(2,4)

tangent of

f (x) = 7 x + 2, (2, 4)

y = \frac{7}{8} x + \frac{9}{4}

Solution steps

Find the slope of

f (x) = 7 x + 2 : \frac{df ( x )}{d x} = \frac{7}{2 7 x + 2}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{7}{8}

Find the line with slope m=

\frac{7}{8}

and passing through

(2, 4) : y = \frac{7}{8} x + \frac{9}{4}

y = \frac{7}{8} x + \frac{9}{4}

x y^{^{'}} + y = e^{x}, y (1) = 1

s l o p e in t erce pt (3, 6), (5, - 8)

\frac{\partial}{\partial x} (ln (x + t^{2}))

\int_{- 2}^{- 1} x f (x^{2} + 1) d x

d er i v a t i v e f (x) = \frac{x}{( x - 1 ) ^{2}}

What is the tangent of f(x)=sqrt(7x+2),(2,4) ?
The tangent of f(x)=sqrt(7x+2),(2,4) is y= 7/8 x+9/4