What is the sum from k=1 to infinity of 1/(k^4) ?

The sum from k=1 to infinity of 1/(k^4) is converges

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sum from k=1 to infinity of 1/(k^4)

k = 1 \sum \infty \frac{1}{k ^{4}}

converges

Solution steps

k = 1 \sum \infty \frac{1}{k ^{4}}

Apply p-Series Test:

converges

= converges

4 x^{2} cos (x) + 3 x

\int 4 e^{x} sec (e^{x} + 2) d x

\int \frac{( x - 1 )}{( x - 1 ) ^{2} + 1} d x

\frac{1}{s ^{\frac{3}{2}}}

6 y^{^{''}} + 31 y = 0, y (0) = 6, y^{^{'}} (0) = 2

What is the sum from k=1 to infinity of 1/(k^4) ?
The sum from k=1 to infinity of 1/(k^4) is converges