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Popular >

area y=x^3,y=4+2x,x=0

Solution

area

y = x^{3}, y = 4 + 2 x, x = 0

Solution

8

Solution steps

Apply the area formula:

\int_{0}^{2} x^{3} - (4 + 2 x) d x

Solve

\int_{0}^{2} x^{3} - (4 + 2 x) d x : 8

The area is:

= 8

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\int \frac{sin ( 2 x )}{26 + cos ^{2} ( x )} d x

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\int \frac{3 x ^{2} + x + 4}{x ^{3} + x} d x

sum from n=1 to infinity of 1/(n^2+3n)

n = 1 \sum \infty \frac{1}{n ^{2} + 3 n}

derivative of f(x)=270 derivative of

f (x) = 270

Frequently Asked Questions (FAQ)

What is area y=x^3,y=4+2x,x=0 ?
The answer to area y=x^3,y=4+2x,x=0 is 8