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Popular >

y^'=e^{4x+3y}

Solution

y^{^{'}} = e^{4 x + 3 y}

Solution

y = - \frac{ln ( - \frac{3}{4} e ^{4 x} - c _{1} )}{3}

Solution steps

y^{'} (x) = e^{4 x + 3 y}

Solve separable ODE:

y = - \frac{ln ( - \frac{3}{4} e ^{4 x} - c _{1} )}{3}

y = - \frac{ln ( - \frac{3}{4} e ^{4 x} - c _{1} )}{3}

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Frequently Asked Questions (FAQ)

What is the solution for y^'=e^{4x+3y} ?
The solution for y^'=e^{4x+3y} is y=-(ln(-3/4 e^{4x}-c_{1}))/3