What is the derivative of (-2/(sqrt(x))) ?

The derivative of (-2/(sqrt(x))) is 1/(x^{3/2)}

What is the first derivative of (-2/(sqrt(x))) ?

The first derivative of (-2/(sqrt(x))) is 1/(x^{3/2)}

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\frac{d}{d x} (\frac{- 2}{x})

\frac{1}{x ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{- 2}{x})

Simplify

\frac{- 2}{x} : - \frac{2}{x}

= \frac{d}{d x} (- \frac{2}{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 2 \frac{d}{d x} (x^{- \frac{1}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 2 (- \frac{1}{2} x^{- \frac{1}{2} - 1})

Simplify

- 2 (- \frac{1}{2} x^{- \frac{1}{2} - 1}) : \frac{1}{x ^{\frac{3}{2}}}

= \frac{1}{x ^{\frac{3}{2}}}

e^{2 x} + 2 x e^{2 x}

\frac{d}{d x} (cos (\frac{1 - e ^{5 x}}{1 + e ^{5 x}}))

\int \frac{1}{6 x ^{2}} d x

\frac{\partial}{\partial x} (2 x + 4 y)

y^{^{'}} - \frac{2 y}{x} = x^{2}

What is the derivative of (-2/(sqrt(x))) ?
The derivative of (-2/(sqrt(x))) is 1/(x^{3/2)}
What is the first derivative of (-2/(sqrt(x))) ?
The first derivative of (-2/(sqrt(x))) is 1/(x^{3/2)}