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Popular Calculus >

area x=2y^2,x=2

Solution

area

x = 2 y^{2}, x = 2

Solution

\frac{8}{3}

+1

Decimal

2.66666 \dots

Solution steps

Isolate

y

for

x = 2 y^{2} : y = \frac{x}{2}, y = - \frac{x}{2}

Apply the area formula:

\int_{0}^{2} 2 x d x

Solve

\int_{0}^{2} 2 x d x : \frac{8}{3}

The area is:

= \frac{8}{3}

Graph

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y^{^{''}} - 2 y^{^{'}} - 15 y = e^{(3 x)} cos (2 x)

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\int \frac{( 1 - z )}{z z} d z

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d er i v a t i v e cos (π x)

limit as x approaches 8 of 88

x \to 8 lim (88)

derivative of f(x)=2^{x^3}

d er i v a t i v e f (x) = 2^{x^{3}}

Frequently Asked Questions (FAQ)

What is area x=2y^2,x=2 ?
The answer to area x=2y^2,x=2 is 8/3