derivative of 1+2tan(x)

解答

\frac{d}{d x} (1 + 2 tan (x))

2 sec^{2} (x)

求解步骤

\frac{d}{d x} (1 + 2 tan (x))

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (2 tan (x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (2 tan (x)) = 2 sec^{2} (x)

= 0 + 2 sec^{2} (x)

化简

= 2 sec^{2} (x)

x \to 0 lim (x^{2} - 1)

\int ln (x) x^{15} d x

t an g e n t \frac{3}{( 4 x + 1 ) ^{2}}

\frac{d}{d x} (\frac{x ^{3}}{3} + 1)

\frac{d}{d x} (2 x - x^{2} + 2 x^{3})