What is the first derivative of x+e ?

The first derivative of x+e is 1

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derivative of x+e

\frac{d}{d x} (x + e)

1

Solution steps

\frac{d}{d x} (x + e)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d e}{d x}

\frac{d x}{d x} = 1

\frac{d e}{d x} = 0

= 1 + 0

Simplify

= 1

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