What is the integral of 2e^{-x^2} ?

The integral of 2e^{-x^2} is sqrt(pi)\erf(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 2e^{-x^2}

\int 2 e^{- x^{2}} d x

π erf (x) + C

Solution steps

\int 2 e^{- x^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int e^{- x^{2}} d x

Use the nonelementary integral:

\int e^{- x^{2}} d x = \frac{π}{2} erf (x)

= 2 \cdot \frac{π}{2} erf (x)

Simplify

2 \cdot \frac{π}{2} erf (x) : π erf (x)

= π erf (x)

Add a constant to the solution

= π erf (x) + C

\frac{d}{d x} (\frac{1}{6} (2 x + 1)^{3})

\frac{d}{d x} (\frac{x - x}{x ^{\frac{1}{4}}})

x \to - 2 lim ((5 x + 7)^{4})

2^{x^{2} - 3}

\int_{- \infty}^{20} r e^{\frac{r}{5}} d r

What is the integral of 2e^{-x^2} ?
The integral of 2e^{-x^2} is sqrt(pi)\erf(x)+C