What is the sum from n=1 to infinity of ((3x)^n)/n ?

The sum from n=1 to infinity of ((3x)^n)/n is Interval of convergence is-1/3 <= x< 1/3

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sum from n=1 to infinity of ((3x)^n)/n

n = 1 \sum \infty \frac{( 3 x ) ^{n}}{n}

Interval of convergence is - \frac{1}{3} \leq x < \frac{1}{3}

Solution steps

n = 1 \sum \infty \frac{( 3 x ) ^{n}}{n}

Use the Ratio Test to compute the convergence interval

Interval of convergence is - \frac{1}{3} \leq x < \frac{1}{3}

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What is the sum from n=1 to infinity of ((3x)^n)/n ?
The sum from n=1 to infinity of ((3x)^n)/n is Interval of convergence is-1/3 <= x< 1/3