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Popular Calculus >

integral of 2x*e^{2x}

  • Pre Algebra
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Solution

∫2x⋅e2xdx

Solution

e2xx−21​e2x+C
Solution steps
∫2xe2xdx
Take the constant out: ∫a⋅f(x)dx=a⋅∫f(x)dx=2⋅∫xe2xdx
Apply u-substitution
=2⋅∫4euu​du
Take the constant out: ∫a⋅f(x)dx=a⋅∫f(x)dx=2⋅41​⋅∫euudu
Apply Integration By Parts
=2⋅41​(euu−∫eudu)
∫eudu=eu
=2⋅41​(euu−eu)
Substitute back u=2x=2⋅41​(e2x⋅2x−e2x)
Simplify 2⋅41​(e2x⋅2x−e2x):e2xx−21​e2x
=e2xx−21​e2x
Add a constant to the solution=e2xx−21​e2x+C

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Frequently Asked Questions (FAQ)

  • What is the integral of 2x*e^{2x} ?

    The integral of 2x*e^{2x} is e^{2x}x-1/2 e^{2x}+C
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