What is the derivative of (-cos(2x)/2) ?

The derivative of (-cos(2x)/2) is sin(2x)

What is the first derivative of (-cos(2x)/2) ?

The first derivative of (-cos(2x)/2) is sin(2x)

\frac{d}{d x} (\frac{- cos ( 2 x )}{2})

sin (2 x)

Solution steps

\frac{d}{d x} (\frac{- cos ( 2 x )}{2})

Simplify

\frac{- cos ( 2 x )}{2} : - \frac{cos ( 2 x )}{2}

= \frac{d}{d x} (- \frac{cos ( 2 x )}{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{1}{2} \frac{d}{d x} (cos (2 x))

Apply the chain rule:

- sin (2 x) \frac{d}{d x} (2 x)

= - sin (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= - \frac{1}{2} (- sin (2 x) \cdot 2)

Simplify

- \frac{1}{2} (- sin (2 x) \cdot 2) : sin (2 x)

= sin (2 x)

x \to - 1 + lim (\frac{3}{x ^{2} - 1})

\frac{d}{d x} ((3 x + 5)^{3})

\int \frac{( z ^{2} + 1 ) ^{2}}{z} d z

\frac{d}{d x} (7 x + 6)

\int csc (9 x) d x

What is the derivative of (-cos(2x)/2) ?
The derivative of (-cos(2x)/2) is sin(2x)
What is the first derivative of (-cos(2x)/2) ?
The first derivative of (-cos(2x)/2) is sin(2x)