What is the integral from 0 to pi of 2sin(x)+sin(2x) ?

The integral from 0 to pi of 2sin(x)+sin(2x) is 4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 0 to pi of 2sin(x)+sin(2x)

\int_{0}^{π} 2 sin (x) + sin (2 x) d x

4

Solution steps

\int_{0}^{π} 2 sin (x) + sin (2 x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{π} 2 sin (x) d x + \int_{0}^{π} sin (2 x) d x

\int_{0}^{π} 2 sin (x) d x = 4

\int_{0}^{π} sin (2 x) d x = 0

= 4 + 0

Simplify

= 4

\int csc (π x) cos (π x) d x

\int cos (nπ t) d t

d er i v a t i v e 11 x \cdot e^{x}

x \to 0 lim (tanh (x))

s l o p e (78) (7 - 9)

What is the integral from 0 to pi of 2sin(x)+sin(2x) ?
The integral from 0 to pi of 2sin(x)+sin(2x) is 4