derivative of 2-(x^2-2x+4/(x-2))

Lösung

\frac{d}{d x} (2 - \frac{x ^{2} - 2 x + 4}{x - 2})

- \frac{x ^{2} - 4 x}{( x - 2 ) ^{2}}

Schritte zur Lösung

\frac{d}{d x} (2 - \frac{x ^{2} - 2 x + 4}{x - 2})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2) - \frac{d}{d x} (\frac{x ^{2} - 2 x + 4}{x - 2})

\frac{d}{d x} (2) = 0

\frac{d}{d x} (\frac{x ^{2} - 2 x + 4}{x - 2}) = \frac{x ^{2} - 4 x}{( x - 2 ) ^{2}}

= 0 - \frac{x ^{2} - 4 x}{( x - 2 ) ^{2}}

Vereinfache

= - \frac{x ^{2} - 4 x}{( x - 2 ) ^{2}}

\int \frac{ln ( x )}{x} d x

x^{2} \frac{d ^{2} y}{d x ^{2}} - 5 x y^{^{'}} + 8 y = 4 x^{2}

\int_{0}^{1} 2 π (x + 1) (x^{2}) d x

t an g e n t y = (3)^{x}, at x = 6

\int \frac{1}{( x + 5 ) ^{2} ( x - 4 )} d x